document.write( "Question 964015: Jan and Tariq took a canoeing trip, traveling 6 mi upstream against a 2-mi/h current. They then returned to the same point downstream. If their entire trip took 4 hr, how fast could they paddle in still water? \n" ); document.write( "
Algebra.Com's Answer #589036 by LinnW(1048)![]() ![]() You can put this solution on YOUR website! Use the formula, rate * time = distance \n" ); document.write( "Set x = speed in still water \n" ); document.write( "(x-2) * t1 = 6 miles \n" ); document.write( "(x+2) * t2 = 6 miles \n" ); document.write( "t1, the time paddling upstream = distance 6 miles/ rate (x-2) or \n" ); document.write( "6/(x-2) \n" ); document.write( "t2, the time paddling downstream = distance 6 miles/ rate (x+2) or \n" ); document.write( "6/(x+2) \n" ); document.write( "t1 + t2 = 4 hours, so \n" ); document.write( "6/(x-2) + 6/(x+2) = 4 \n" ); document.write( "A common denominator is (x-2)(x+2) so we want \n" ); document.write( " \n" ); document.write( "expanding \n" ); document.write( " \n" ); document.write( "simplify \n" ); document.write( " \n" ); document.write( "do cross products \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "divide by 4 \n" ); document.write( " \n" ); document.write( "factoring \n" ); document.write( " \n" ); document.write( "So possible values for x are 4 and -1 \n" ); document.write( "Since we need a positive speed, the speed in \n" ); document.write( "still water is 4 mph \n" ); document.write( " |