document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=964126>Question 964126</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The manager of a coffee shop has one type of coffee that sells for $7 per pound and another type that sells for $13 per pound.\r<BR>\n" );
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document.write( "The manager wishes to mix 70 pounds of the $13 coffee to get a mixture that will sell for $8 per pound.\r<BR>\n" );
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document.write( "How many pounds of the $7 coffee should be used?<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #589016 by </B><A HREF=/tutors/aboutme.mpl?userid=macston><B>macston(5194)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=macston><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=macston><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=589016\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> .<BR>\n" );
document.write( "S=amount of $7/lb coffee to add.<BR>\n" );
document.write( "$13(70lbs)+$7(S)=$8(S+70lbs)<BR>\n" );
document.write( "$910lbs+$7S=$8S+$560lbs Subtract $7s+$560lbs from each side.<BR>\n" );
document.write( "$350lbs=$1SDivide by $1<BR>\n" );
document.write( "350lbs=S She should add 350 lbs of the $7/lb coffee.<BR>\n" );
document.write( "CHECK:<BR>\n" );
document.write( "$13(70)+$7(350)=$8(420)<BR>\n" );
document.write( "$910+$2450=$3360<BR>\n" );
document.write( "$3360=$3360<BR>\n" );
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