document.write( "Question 964092: A rectangular park measuring 31 yards by 27yards is surrounded by a trial of uniform width. If the area of the park and the trial combined is 2205 square yards, what is the width of the path? \n" ); document.write( "
Algebra.Com's Answer #588987 by addingup(3677)![]() ![]() You can put this solution on YOUR website! 1) The trail around the park is all the same width, like the frame on a picture. \n" ); document.write( "2) The area of a rectangle = l x w \n" ); document.write( "3) A rectangle has 2 lengths and 2 widths. Let's call the width of the trail x: \n" ); document.write( "(31+2x)(27+2x)= 2205 Multiply (FOIL) \n" ); document.write( "31*27+31*2x+2x*27+4x^2 = 2205 \n" ); document.write( "= 837+62x+54x+4x^2 = 2205 \n" ); document.write( "=837+116x+4x^2 = 2205 Let's rewrite as a quadratic polynomial: \n" ); document.write( "4x^2+116x+837= 2205 Divide both sides by 4: \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "Length: 31+ 2(9)= 49 \n" ); document.write( "Width: 27+2(9)= 45 \n" ); document.write( "Area of the park with the trail: \n" ); document.write( "49*45= 2205 We've got the correct answer. See the sketch I made you: \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " |