document.write( "Question 964085: Each side of a square is increased 6 inches. When this happens, the area is multiplied by 25. How many inches in the side of the original square? \n" ); document.write( "
Algebra.Com's Answer #588965 by macston(5194)\"\" \"About 
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s=original side
\n" ); document.write( "\"%28s%2B6%29%5E2=25s%5E2\"
\n" ); document.write( "\"s%5E2%2B12s%2B36=25s%5E2\" Subtract 25s^2 from each side.
\n" ); document.write( "\"-24s%5E2%2B12S%2B36=0\" Divide each side by -12.
\n" ); document.write( "\"2s%5E2-s-3=0\"\n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( "
Solved by pluggable solver: SOLVE quadratic equation with variable
Quadratic equation \"as%5E2%2Bbs%2Bc=0\" (in our case \"2s%5E2%2B-1s%2B-3+=+0\") has the following solutons:
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\n" ); document.write( " \"s%5B12%5D+=+%28b%2B-sqrt%28+b%5E2-4ac+%29%29%2F2%5Ca\"
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\n" ); document.write( " For these solutions to exist, the discriminant \"b%5E2-4ac\" should not be a negative number.
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\n" ); document.write( " First, we need to compute the discriminant \"b%5E2-4ac\": \"b%5E2-4ac=%28-1%29%5E2-4%2A2%2A-3=25\".
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\n" ); document.write( " Discriminant d=25 is greater than zero. That means that there are two solutions: \"+x%5B12%5D+=+%28--1%2B-sqrt%28+25+%29%29%2F2%5Ca\".
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\n" ); document.write( " \"s%5B1%5D+=+%28-%28-1%29%2Bsqrt%28+25+%29%29%2F2%5C2+=+1.5\"
\n" ); document.write( " \"s%5B2%5D+=+%28-%28-1%29-sqrt%28+25+%29%29%2F2%5C2+=+-1\"
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\n" ); document.write( " Quadratic expression \"2s%5E2%2B-1s%2B-3\" can be factored:
\n" ); document.write( " \"2s%5E2%2B-1s%2B-3+=+2%28s-1.5%29%2A%28s--1%29\"
\n" ); document.write( " Again, the answer is: 1.5, -1.\n" ); document.write( "Here's your graph:
\n" ); document.write( "\"graph%28+500%2C+500%2C+-10%2C+10%2C+-20%2C+20%2C+2%2Ax%5E2%2B-1%2Ax%2B-3+%29\"

\n" ); document.write( "\n" ); document.write( "So s=1.5 inches.
\n" ); document.write( "ANSWER: The sides of the original square were 1.5 inches.
\n" ); document.write( "CHECK:
\n" ); document.write( "Original area=\"%281.5in%29%5E2=2.25in%5E2\"
\n" ); document.write( "\"%281.5in%2B6in%29%5E2=25%282.25in%5E2%29\"
\n" ); document.write( "\"%287.5in%29%5E2=56.25in%5E2\"
\n" ); document.write( "\"56.25in%5E2=56.25in%5E2\"\r
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