document.write( "Question 963586: The combined area of a square and a rectangle is 201 square centimeters. The width of the rectangle is 5 centimeters more than the length of a side of the square, and the length of the rectangle is 4 centimeters more than its width. Find the dimensions of the square and the rectangle. \n" ); document.write( "
Algebra.Com's Answer #588950 by macston(5194)![]() ![]() You can put this solution on YOUR website! . \n" ); document.write( ". \n" ); document.write( "s=Side of square; W=width of rectangle=s+5cm; L=length of rectangle=W+4cm=s+9cm \n" ); document.write( "Area of square=s^2; Area of rectangle=(L)(W) \n" ); document.write( "Total Area=area of square + area of rectangle \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "ANSWER 1: The sides of the square are 6 cm \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "CHECK: \n" ); document.write( "Total Area = area of square + area of rectangle \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |