document.write( "Question 963586: The combined area of a square and a rectangle is 201 square centimeters. The width of the rectangle is 5 centimeters more than the length of a side of the square, and the length of the rectangle is 4 centimeters more than its width. Find the dimensions of the square and the rectangle. \n" ); document.write( "
Algebra.Com's Answer #588950 by macston(5194)\"\" \"About 
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\n" ); document.write( ".
\n" ); document.write( "s=Side of square; W=width of rectangle=s+5cm; L=length of rectangle=W+4cm=s+9cm
\n" ); document.write( "Area of square=s^2; Area of rectangle=(L)(W)
\n" ); document.write( "Total Area=area of square + area of rectangle
\n" ); document.write( "\"201cm%5E2=s%5E2%2B%28L%29%28W%29\"
\n" ); document.write( "\"201cm%5E2=s%5E2%2B%28s%2B9cm%29%28s%2B5cm%29\"
\n" ); document.write( "\"201cm%5E2=s%5E2%2Bs%5E2%2B14s%2B45%29\"
\n" ); document.write( "\"0=2s%5E2%2B14s-156\"
\n" ); document.write( "\"0=s%5E2%2B7s-78\"
\n" ); document.write( "\"0=%28s%2B13%29%28s-6%29\"
\n" ); document.write( "\"s%2B13=0\" or \"s-6=0\"
\n" ); document.write( "\"s=-13\" \"or\" \"s=6\"
\n" ); document.write( "ANSWER 1: The sides of the square are 6 cm
\n" ); document.write( "\"W=s%2B5cm\"=\"6cm%2B5cm=11cm\" ANSWER 2: The width of the rectangle is 11 cm.
\n" ); document.write( "\"L=W%2B4cm\"=\"11cm%2B4cm=15cm\" ANSWER 3: The length of the rectangle is 15 cm.
\n" ); document.write( "CHECK:
\n" ); document.write( "Total Area = area of square + area of rectangle
\n" ); document.write( "\"201cm%5E2=s%5E2%2B%28L%29%28W%29\"
\n" ); document.write( "\"201cm%5E2=%286cm%29%5E2%2B%2811cm%29%2815cm%29\"
\n" ); document.write( "\"201cm%5E2=36cm%5E2%2B165cm%5E2\"
\n" ); document.write( "\"201cm%5E2=201cm%5E2\"\r
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