document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=964031>Question 964031</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Type Your QuestionTwo cars leave town's for 400 km apart at the same time and travel toward each other. One car's rate is 10 km per hour less than the others. If they me in 2 hours what is the rate of the slower car? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #588920 by </B><A HREF=/tutors/aboutme.mpl?userid=lwsshak3><B>lwsshak3(11628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=lwsshak3><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=588920\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Type Your QuestionTwo cars leave town's for 400 km apart at the same time and travel toward each other. One car's rate is 10 km per hour less than the others. If they me in 2 hours what is the rate of the slower car?<BR>\n" );
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document.write( "x=rate of slower car<BR>\n" );
document.write( "x+10=rate of faster car<BR>\n" );
document.write( "The 2 cars are moving toward each other at a rate=x+(10+x)=2x+10<BR>\n" );
document.write( "travel time=distance/rate<BR>\n" );
document.write( "400/(2x+10)=2<BR>\n" );
document.write( "4x+20=400<BR>\n" );
document.write( "4x=380<BR>\n" );
document.write( "x=95<BR>\n" );
document.write( "what is the rate of the slower car? 95 km/hr </SPAN>\n" );
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