document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=964018>Question 964018</A>: <I><SPAN STYLE=\"word-break: break-all;\"> solve for x.<BR>\n" );
document.write( "2^(x^2-x+10)=16^(7-x)<BR>\n" );
document.write( "if there is more than one solution, separate them with commas. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #588909 by </B><A HREF=/tutors/aboutme.mpl?userid=Murthy><B>Murthy(22)</B></A><img src=\"/images/stars/stars-07.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Murthy><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=588909\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 2^(x^2-x+10)=16^(7-x)\r<BR>\n" );
document.write( "\n" );
document.write( "Taking log with base 2 on both sides\r<BR>\n" );
document.write( "\n" );
document.write( "(x^2-x+10)x log2(2)= (7-x)x log2(2^4)\r<BR>\n" );
document.write( "\n" );
document.write( "=(x^2-x+10)x log(2)=(7-x)x 4xlog2(2)\r<BR>\n" );
document.write( "\n" );
document.write( "cancel log2(2)on both sides\r<BR>\n" );
document.write( "\n" );
document.write( "(x^2-x+10)=4(7-x)\r<BR>\n" );
document.write( "\n" );
document.write( "x^2+3x-18=0\r<BR>\n" );
document.write( "\n" );
document.write( "(x+6)(x-3)=0\r<BR>\n" );
document.write( "\n" );
document.write( "therefore,\r<BR>\n" );
document.write( "\n" );
document.write( "x=-6,3<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );