document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=964006>Question 964006</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A piece of wire 5.5 m long is bent into a triangular shape. One side is 1.5m long and another is 2m long. Find the angles of the triangle. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #588902 by </B><A HREF=/tutors/aboutme.mpl?userid=amarjeeth123><B>amarjeeth123(569)</B></A><img src=\"/images/stars/stars-10.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=amarjeeth123><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=588902\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> A piece of wire 5.5 m long is bent into a triangular shape. One side is 1.5m long and another is 2m long.The third side is 5.5-(2+1.5)=2m<BR>\n" );
document.write( "The sides of the triangle are 2m,2m and 1.5m respectively.<BR>\n" );
document.write( "Let the angle opposite to 1.5 m be x.<BR>\n" );
document.write( "using cosine rule we get a^2=b^2+c^2-2bccosA<BR>\n" );
document.write( "Substituting the values we get,<BR>\n" );
document.write( "1.5^2=2^2+2^2-2(2)(2)cosx<BR>\n" );
document.write( "2.25=4+4-8cosx<BR>\n" );
document.write( "8cosx=8-2.25<BR>\n" );
document.write( "8cosx=5.75<BR>\n" );
document.write( "cosx=0.71875<BR>\n" );
document.write( "x=44 degrees<BR>\n" );
document.write( "Since two sides are equal two angles are equal and it is an isosceles triangle.<BR>\n" );
document.write( "Let the other two angles be y<BR>\n" );
document.write( "2y+44=180<BR>\n" );
document.write( "2y=136<BR>\n" );
document.write( "y=68<BR>\n" );
document.write( "The angles of the triangle are 68,68 and 44 degrees. </SPAN>\n" );
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