document.write( "Question 963991: The perimeter of a rectangle is 26 and its diagonal is √97. Find its length and width. \r
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Algebra.Com's Answer #588894 by josgarithmetic(39625)\"\" \"About 
You can put this solution on YOUR website!
x and y, the dimensions.\r
\n" ); document.write( "\n" ); document.write( "\"2x%2B2y=26\", for perimeter information.
\n" ); document.write( "This simplifies to \"x%2By=13\".\r
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\n" ); document.write( "\n" ); document.write( "Diagonal, \"sqrt%2897%29=sqrt%28x%5E2%2By%5E2%29\".\r
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\n" ); document.write( "\n" ); document.write( "Square both sides, \"97=x%5E2%2By%5E2\"
\n" ); document.write( "and make a substitution for either variable.
\n" ); document.write( "\"y=13-x\"
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\n" ); document.write( "\"x%5E2%2B%2813-x%29%5E2=97\"
\n" ); document.write( "\"x%5E2%2B169-26x%2Bx%5E2-97=0\"
\n" ); document.write( "\"2x%5E2-26x%2B169-97=0\"
\n" ); document.write( "\"2x%5E2-26x%2B72=0\"
\n" ); document.write( "\"x%5E2-13x%2B36=0\"
\n" ); document.write( "\"highlight_green%28%28x-4%29%28x-9%29=0%29\"\r
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\n" ); document.write( "\n" ); document.write( "Since either x or y could stand for either dimension, the two dimensions' sizes
\n" ); document.write( "are 4 and 9.
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