document.write( "Question 963925: what is the equation of the line that passes through (–2, 4) and is perpendicular to 6x + 3y = 2\r
\n" ); document.write( "\n" ); document.write( "A.) 1/3x + 1/2y = 2 \r
\n" ); document.write( "\n" ); document.write( "B.) x - 2y = -10 \r
\n" ); document.write( "\n" ); document.write( "C.) 2x - y = 10 \r
\n" ); document.write( "\n" ); document.write( "D.) 2x + 3y =6
\n" ); document.write( "

Algebra.Com's Answer #588869 by MathTherapy(10552)\"\" \"About 
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\n" ); document.write( "what is the equation of the line that passes through (–2, 4) and is perpendicular to 6x + 3y = 2\r
\n" ); document.write( "\n" ); document.write( "A.) 1/3x + 1/2y = 2 \r
\n" ); document.write( "\n" ); document.write( "B.) x - 2y = -10 \r
\n" ); document.write( "\n" ); document.write( "C.) 2x - y = 10 \r
\n" ); document.write( "\n" ); document.write( "D.) 2x + 3y =6
\n" ); document.write( "
Slope of line with equation, 6x + 3y = 2 is: - 2
\n" ); document.write( "Slope of line perpendicular to line with equation, 6x + 3y = 2 is: \"1%2F2\"
\n" ); document.write( "Using this slope, and the point, (- 2, 4) should give you the correct equation.
\n" ); document.write( "Only one (1) equation has a slope, or m of \"1%2F2\" \n" ); document.write( "
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