document.write( "Question 963867: A principal of
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document.write( "$1300
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document.write( " is invested at
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document.write( "8.75%
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document.write( " interest, compounded annually. How many years will it take to accumulate
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document.write( "$4000
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document.write( " or more in the account? \n" );
document.write( "
Algebra.Com's Answer #588842 by nerdybill(7384)![]() ![]() You can put this solution on YOUR website! A principal of \n" ); document.write( "$1300 \n" ); document.write( " is invested at \n" ); document.write( "8.75% \n" ); document.write( " interest, compounded annually. How many years will it take to accumulate \n" ); document.write( "$4000 \n" ); document.write( " or more in the account? \n" ); document.write( ". \n" ); document.write( "Use: \n" ); document.write( "A = P(1+i)^t \n" ); document.write( "where \n" ); document.write( "A is amount after time t (4000) \n" ); document.write( "P is principal (1300) \n" ); document.write( "i is interest (.075) \n" ); document.write( "t is time (years) -- this is what we're looking for \n" ); document.write( ". \n" ); document.write( "4000 = 1300(1+.075)^t \n" ); document.write( "4000 = 1300(1.075)^t \n" ); document.write( "40 = 13(1.075)^t \n" ); document.write( "40/13 = (1.075)^t \n" ); document.write( " \n" ); document.write( "15.54 years = t \n" ); document.write( "answer: approximately 16 years \n" ); document.write( " \n" ); document.write( " |