document.write( "Question 963677: Find the domain and range of the given function. Explain your answers.\r
\n" ); document.write( "\n" ); document.write( "H(h)= 2h + 3 sqrt h + 10\r
\n" ); document.write( "\n" ); document.write( "So far I have figured out that the domain is: All real numbers h greater than or equal to 0. And the range is: All real numbers H(h)=10. If these are incorrect, what did I do wrong, and what should they be?\r
\n" ); document.write( "\n" ); document.write( "I need an explanation for both the domain and range. I do not understand how to verbally explain why the domain and range are what they are. \n" ); document.write( "

Algebra.Com's Answer #588833 by Fombitz(32388) $\"\"$ $\"About$

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Domain: Because the square root function, which is one of the components of the function, requires a non-negative argument so this forces the domain to be non-negative.
\n" ); document.write( "Range: Each of the individual functions that make up the entire function are positive function and the entire function is the sum of the three functions. The minimum of $\"2h\"$ occurs at $\"h=0\"$ as does the minimum of $\"3sqrt%28h%29\"$ . Both these values are $\"0\"$ so the only term that contributes to the value is the constant term $\"10\"$ . So the minimum of the function is $\"H=10\"$ and the maximum if unbounded making the range [ $\"10\"$ , $\"infinity\"$ ). \n" ); document.write( "

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