document.write( "Question 963807: 10 years ago Ashraf's mother was four times older than her daughter. After 10 years, the mother will be twice older than daughter. The present age of Ashraf is? \n" ); document.write( "
Algebra.Com's Answer #588793 by macston(5194)![]() ![]() You can put this solution on YOUR website! A=Ashraf's age; M=mother's age \n" ); document.write( "M-10=4(A-10) \n" ); document.write( "M-10=4A-40 \n" ); document.write( "M=4A-30 Use this to substitute for M below. \n" ); document.write( "M+10=2(A+10) \n" ); document.write( "M+10=2A+20 \n" ); document.write( "M=2A+10 Substitute for M from above. \n" ); document.write( "4A-30=2A+10 Add 30 to each side \n" ); document.write( "4A=2A+40 Subtract 2A from each side. \n" ); document.write( "2A=40 Divide each side by 2. \n" ); document.write( "A=20 ANSWER: Ashraf is 20 years old. \n" ); document.write( "CHECK: \n" ); document.write( "M=4A-30=4(20)-30=80-30=50 Mother is 50 years old. \n" ); document.write( "M+10=2(A+10) \n" ); document.write( "50+10=2(20+10) \n" ); document.write( "60=2(30) \n" ); document.write( "60=60 \n" ); document.write( " |