document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=963789>Question 963789</A>: <I><SPAN STYLE=\"word-break: break-all;\"> My question is: The dimensions of a triangle are multiplied by 1/4.  The area of a smaller triangle can be found by multiplying the area of the original triangle by what number?\r<BR>\n" );
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document.write( "It seems too simple to say the answer is 1/4, but that's the only thing that makes sense to me.  This is for 6th grade math.  Thank you for any help you can provide! </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #588789 by </B><A HREF=/tutors/aboutme.mpl?userid=rothauserc><B>rothauserc(4718)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=rothauserc><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=rothauserc><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=588789\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> let's pick a 3, 4, 5 right triangle,  we know that<BR>\n" );
document.write( "Area(A) of triangle = (1/2) * base * height<BR>\n" );
document.write( "In the case of our triangle,<BR>\n" );
document.write( "A = (1/2) * 3 * 4 = 6<BR>\n" );
document.write( "now if we divide the dimensions by 4<BR>\n" );
document.write( "A = (1/2) * (3/4) * (4/4) = (3/8)<BR>\n" );
document.write( "so we want to solve,<BR>\n" );
document.write( "6/x = 3/8<BR>\n" );
document.write( "cross multiply fractions<BR>\n" );
document.write( "3x = 48<BR>\n" );
document.write( "x = 16<BR>\n" );
document.write( "therefore,<BR>\n" );
document.write( "we multiply the area of the larger triangle by (1/16)<BR>\n" );
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document.write( "lets check our rule with an isosceles right triangle which has sides 1, 1, sqrt(2)<BR>\n" );
document.write( "A = (1/2) * 1 * 1 = (1/2)<BR>\n" );
document.write( "also<BR>\n" );
document.write( "A of smaller triangle = (1/2) * (1/4) * (1/4) = (1/32)<BR>\n" );
document.write( "so we see that if we multiply (1/2) * (1/16) our rule works for a 1, 1, sqrt(2) isosceles right triangle also<BR>\n" );
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