document.write( "Question 963725: MOVIE TICKETS COST $5 FOR ADULTS AND $2 FOR CHILDREN. ON ONE DAY 785 TICKETS WERE SOLD FOR $3280. HOW MANY CHILDREN'S TICKETS WERE SOLD? \n" ); document.write( "
Algebra.Com's Answer #588766 by macston(5194)![]() ![]() You can put this solution on YOUR website! A=number of adult tickets; C=number of child tickets \n" ); document.write( "A+C=785 \n" ); document.write( "A=785-C Use this to substitute for A. \n" ); document.write( "$5A+$2C=$3280 Substitute for A. \n" ); document.write( "$5(785-C)+$2C=$3280 \n" ); document.write( "$3925-$5C+$2C=$3280 Subtract $3925 from each side. \n" ); document.write( "-$3C=-$645 Divide each side by -$3 \n" ); document.write( "C=215 ANSWER There were 215 child tickets sold. \n" ); document.write( "CHECK: \n" ); document.write( "A=785-C=785-215=570 \n" ); document.write( "$5A+$2C=$3280 \n" ); document.write( "$5(570)+$2(215)=$3280 \n" ); document.write( "$2850+$430=$3280 \n" ); document.write( "$3280=$3280 \n" ); document.write( " \n" ); document.write( " |