document.write( "Question 963400: (Y+5)^2=-4X+28
\n" ); document.write( "Whats the directrix, vertex, and focus?
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Algebra.Com's Answer #588577 by lwsshak3(11628)\"\" \"About 
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(Y+5)^2=-4X+28
\n" ); document.write( "Whats the directrix, vertex, and focus?
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\n" ); document.write( "(y+5)^2=-4(x-7)
\n" ); document.write( "This is an equation of a parabola that opens leftward
\n" ); document.write( "Its basic equation: (y-k)^2=4p(x-k), (h,k)=coordinates of the vertex
\n" ); document.write( "For given equation:
\n" ); document.write( "vertex: (7,-5)
\n" ); document.write( "4p=4
\n" ); document.write( "p=1
\n" ); document.write( "axis of symmetry: y=5
\n" ); document.write( "focus: (6,-5) (p-distance left of vertex on the axis of symmetry)
\n" ); document.write( "directrix: x=8 (p-distance right of vertex on the axis of symmetry)
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