document.write( "Question 963414: The length of a field is 200ft longer than it is wide. The area of the field is 57,600 sq. ft. What is the width of the field? \n" ); document.write( "
Algebra.Com's Answer #588567 by amarjeeth123(569)\"\" \"About 
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Let the width be x.
\n" ); document.write( "Then the length is (x+200)
\n" ); document.write( "The area of the field=57600
\n" ); document.write( "Area=length*width
\n" ); document.write( "x(x+200)=57600
\n" ); document.write( "x^2+200x-57600=0
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Solved by pluggable solver: SOLVE quadratic equation with variable
Quadratic equation \"ax%5E2%2Bbx%2Bc=0\" (in our case \"1x%5E2%2B200x%2B-57600+=+0\") has the following solutons:
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\n" ); document.write( " \"x%5B12%5D+=+%28b%2B-sqrt%28+b%5E2-4ac+%29%29%2F2%5Ca\"
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\n" ); document.write( " For these solutions to exist, the discriminant \"b%5E2-4ac\" should not be a negative number.
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\n" ); document.write( " First, we need to compute the discriminant \"b%5E2-4ac\": \"b%5E2-4ac=%28200%29%5E2-4%2A1%2A-57600=270400\".
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\n" ); document.write( " Discriminant d=270400 is greater than zero. That means that there are two solutions: \"+x%5B12%5D+=+%28-200%2B-sqrt%28+270400+%29%29%2F2%5Ca\".
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\n" ); document.write( " \"x%5B1%5D+=+%28-%28200%29%2Bsqrt%28+270400+%29%29%2F2%5C1+=+160\"
\n" ); document.write( " \"x%5B2%5D+=+%28-%28200%29-sqrt%28+270400+%29%29%2F2%5C1+=+-360\"
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\n" ); document.write( " Quadratic expression \"1x%5E2%2B200x%2B-57600\" can be factored:
\n" ); document.write( " \"1x%5E2%2B200x%2B-57600+=+1%28x-160%29%2A%28x--360%29\"
\n" ); document.write( " Again, the answer is: 160, -360.\n" ); document.write( "Here's your graph:
\n" ); document.write( "\"graph%28+500%2C+500%2C+-10%2C+10%2C+-20%2C+20%2C+1%2Ax%5E2%2B200%2Ax%2B-57600+%29\"

\n" ); document.write( "\n" ); document.write( "x=160 or x=-360
\n" ); document.write( "The width of the field is 160 feet.
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