document.write( "Question 82110: the length of a rectangle is 8 in more than twice its width. if the perimeter of the rectangle is 58 in, find the width of the rectangle. \n" ); document.write( "
Algebra.Com's Answer #58855 by weepingwillowcats(10)\"\" \"About 
You can put this solution on YOUR website!
In order to solve this, you need to set up an equation.
\n" ); document.write( "First we'll find the length.
\n" ); document.write( "The length is going to be twice the width, so l = 2w.
\n" ); document.write( "Then it also says it's eight more than twice the width, so l = 2w+8.
\n" ); document.write( "Now, set up your equation for the perimeter (add all the sides).
\n" ); document.write( "2w + 8 + 2w + 8 + w + w = 58
\n" ); document.write( "Combine like-terms.
\n" ); document.write( "6w + 16 = 58
\n" ); document.write( "Subtract 16 from both sides.
\n" ); document.write( "6w = 42
\n" ); document.write( "Divide by six on both sides.
\n" ); document.write( "w = 7
\n" ); document.write( "To check your answer, simply plug the answer back into the equation.
\n" ); document.write( "Also, if you have any further questions, don't hesitate to ask.
\n" ); document.write( "Good luck!
\n" ); document.write( "-weepingwillowcats
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