document.write( "Question 82110: the length of a rectangle is 8 in more than twice its width. if the perimeter of the rectangle is 58 in, find the width of the rectangle. \n" ); document.write( "
Algebra.Com's Answer #58855 by weepingwillowcats(10)![]() ![]() ![]() You can put this solution on YOUR website! In order to solve this, you need to set up an equation. \n" ); document.write( "First we'll find the length. \n" ); document.write( "The length is going to be twice the width, so l = 2w. \n" ); document.write( "Then it also says it's eight more than twice the width, so l = 2w+8. \n" ); document.write( "Now, set up your equation for the perimeter (add all the sides). \n" ); document.write( "2w + 8 + 2w + 8 + w + w = 58 \n" ); document.write( "Combine like-terms. \n" ); document.write( "6w + 16 = 58 \n" ); document.write( "Subtract 16 from both sides. \n" ); document.write( "6w = 42 \n" ); document.write( "Divide by six on both sides. \n" ); document.write( "w = 7 \n" ); document.write( "To check your answer, simply plug the answer back into the equation. \n" ); document.write( "Also, if you have any further questions, don't hesitate to ask. \n" ); document.write( "Good luck! \n" ); document.write( "-weepingwillowcats \n" ); document.write( " |