document.write( "Question 82156: the length of a rectangle is 8 in more than twice its width. if the perimeter of the rectangle is 58 in, find the width of the rectangle\r
\n" ); document.write( "\n" ); document.write( "a)6 in
\n" ); document.write( "b)7 in
\n" ); document.write( "c)8 in
\n" ); document.write( "d)9 in
\n" ); document.write( "

Algebra.Com's Answer #58852 by checkley75(3666)\"\" \"About 
You can put this solution on YOUR website!
L=2W+8
\n" ); document.write( "P=2L+2W
\n" ); document.write( "58=2(2W+8)+2W
\n" ); document.write( "58=4W+16+2W
\n" ); document.write( "58=6W+16
\n" ); document.write( "6W=58-16
\n" ); document.write( "6W=42
\n" ); document.write( "W=42/6
\n" ); document.write( "W=7 ANSWER IS C) 7 INCHES.
\n" ); document.write( "PROOF
\n" ); document.write( "58=2(2*7+8)+2*7
\n" ); document.write( "58=2(14+8)+14
\n" ); document.write( "58=2*22+14
\n" ); document.write( "58=44+14
\n" ); document.write( "58=58\r
\n" ); document.write( "\n" ); document.write( "
\n" ); document.write( "
\n" );