document.write( "Question 82156: the length of a rectangle is 8 in more than twice its width. if the perimeter of the rectangle is 58 in, find the width of the rectangle\r
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document.write( "a)6 in
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document.write( "b)7 in
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document.write( "c)8 in
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document.write( "d)9 in \n" );
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Algebra.Com's Answer #58852 by checkley75(3666)![]() ![]() ![]() You can put this solution on YOUR website! L=2W+8 \n" ); document.write( "P=2L+2W \n" ); document.write( "58=2(2W+8)+2W \n" ); document.write( "58=4W+16+2W \n" ); document.write( "58=6W+16 \n" ); document.write( "6W=58-16 \n" ); document.write( "6W=42 \n" ); document.write( "W=42/6 \n" ); document.write( "W=7 ANSWER IS C) 7 INCHES. \n" ); document.write( "PROOF \n" ); document.write( "58=2(2*7+8)+2*7 \n" ); document.write( "58=2(14+8)+14 \n" ); document.write( "58=2*22+14 \n" ); document.write( "58=44+14 \n" ); document.write( "58=58\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |