document.write( "Question 963141: how much solution of 20% acid, must be added to a solution of 35% acid to get 60 gallons of a 25% solution? \n" ); document.write( "
Algebra.Com's Answer #588419 by lwsshak3(11628)\"\" \"About 
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how much solution of 20% acid, must be added to a solution of 35% acid to get 60 gallons of a 25% solution?
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\n" ); document.write( "let x=amt of 20% solution must be added
\n" ); document.write( "60-x=amt of 35% solution must be added
\n" ); document.write( "amt of acid on left side=amt of acid on right side
\n" ); document.write( "..
\n" ); document.write( "20%x+35%(60-x)=25%*60
\n" ); document.write( ".20x+21-.35x=15
\n" ); document.write( ".15x=6
\n" ); document.write( "x=40
\n" ); document.write( "60-x=20
\n" ); document.write( "amt of 20% solution must be added=40 gal.
\n" ); document.write( "amt of 35% solution must be added=20 gal.
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