document.write( "Question 963141: how much solution of 20% acid, must be added to a solution of 35% acid to get 60 gallons of a 25% solution? \n" ); document.write( "
Algebra.Com's Answer #588419 by lwsshak3(11628)![]() ![]() ![]() You can put this solution on YOUR website! how much solution of 20% acid, must be added to a solution of 35% acid to get 60 gallons of a 25% solution? \n" ); document.write( "*** \n" ); document.write( "let x=amt of 20% solution must be added \n" ); document.write( "60-x=amt of 35% solution must be added \n" ); document.write( "amt of acid on left side=amt of acid on right side \n" ); document.write( ".. \n" ); document.write( "20%x+35%(60-x)=25%*60 \n" ); document.write( ".20x+21-.35x=15 \n" ); document.write( ".15x=6 \n" ); document.write( "x=40 \n" ); document.write( "60-x=20 \n" ); document.write( "amt of 20% solution must be added=40 gal. \n" ); document.write( "amt of 35% solution must be added=20 gal. \n" ); document.write( " |