document.write( "Question 82145: How do I solve this equation by substitution?\r
\n" ); document.write( "\n" ); document.write( "5x-2y=-5
\n" ); document.write( "y-5x=3 \n" ); document.write( "
Algebra.Com's Answer #58841 by tutorcecilia(2152)\"\" \"About 
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y-5x=3
\n" ); document.write( "y=5x+3 [solve for the y-term]\r
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\n" ); document.write( "5x-2y=-5
\n" ); document.write( "5x-2(5x+3)=-5 [plug-in (y=5x+3) and solve for the x-term. use the other equation]
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\n" ); document.write( "5x-10x-6=-5
\n" ); document.write( "-5x-6=-5
\n" ); document.write( "-5x-6+6=-5+6
\n" ); document.write( "-5x=1
\n" ); document.write( "-5x/-1=1/-1
\n" ); document.write( "x=-1 [plug-in (x=-1) and solve for the y-term. use either equation]
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\n" ); document.write( "y-5(-1)=3
\n" ); document.write( "y+5=3
\n" ); document.write( "y+5-5=3-5
\n" ); document.write( "y=-2
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\n" ); document.write( "Check by plugging (y=-2)and x=-1) back into either equation and solve:
\n" ); document.write( "y-5x=3
\n" ); document.write( "-2-5(-1)=3
\n" ); document.write( "-2+5=3
\n" ); document.write( "3=3 [checks out]\r
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