document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=963133>Question 963133</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The length of a rectangle is <BR>\n" );
document.write( "3 ft<BR>\n" );
document.write( " more than twice the width, and the area of the rectangle is <BR>\n" );
document.write( "54 ft2<BR>\n" );
document.write( ". Find the dimensions of the rectangle. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #588405 by </B><A HREF=/tutors/aboutme.mpl?userid=amarjeeth123><B>amarjeeth123(569)</B></A><img src=\"/images/stars/stars-10.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=amarjeeth123><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=588405\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let the width be x feet.<BR>\n" );
document.write( "Then the length is 2x+3 feet.<BR>\n" );
document.write( "Area of the rectangle is 54 ft2.<BR>\n" );
document.write( "Area=length*width<BR>\n" );
document.write( "x(2x+3)=54<BR>\n" );
document.write( "2x^2+3x-54=0<BR>\n" );
document.write( "2x^2+12x-9x-54=0<BR>\n" );
document.write( "2x(x+6)-9(x+6)=0<BR>\n" );
document.write( "(2x-9)(x+6)=0<BR>\n" );
document.write( "x=9/2 is the solution as x cannot be negative.<BR>\n" );
document.write( "The width is 4.5 feet.<BR>\n" );
document.write( "The length is 12 feet.<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );