document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=963115>Question 963115</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The area of a rectangular field is 150 yd. if it's length is 1 1/2 times its width, find the perimeter of the field? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #588398 by </B><A HREF=/tutors/aboutme.mpl?userid=amarjeeth123><B>amarjeeth123(569)</B></A><img src=\"/images/stars/stars-10.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=amarjeeth123><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=588398\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let the width be x.<BR>\n" );
document.write( "Then the length is 1.5x.<BR>\n" );
document.write( "The area of a rectangular field is 150 square yd.<BR>\n" );
document.write( "Area=length*width<BR>\n" );
document.write( "1.5x*x=150<BR>\n" );
document.write( "x^2=100<BR>\n" );
document.write( "x=10 yards<BR>\n" );
document.write( "Width=10 yards<BR>\n" );
document.write( "Length=15 yards<BR>\n" );
document.write( "Perimeter of the field=2(length+width)=2(15+10)=2*25=50 yards. </SPAN>\n" );
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