document.write( "Question 963106: How to solve using the substitution method
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document.write( "x^2+y=5
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document.write( "x-y+3=0
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Algebra.Com's Answer #588396 by amarjeeth123(569)![]() ![]() ![]() You can put this solution on YOUR website! The given equations are \n" ); document.write( "x^2+y=5.........equation 1 \n" ); document.write( "x-y+3=0.........equation 2 \n" ); document.write( "From equation 2 we get y=x+3.....equation 3 \n" ); document.write( "Substituting in equation 1 \n" ); document.write( "x^2+x+3=5 \n" ); document.write( "x^2+x-2=0 \n" ); document.write( "x^2+2x-x-2=0 \n" ); document.write( "x(x+2)-1(x+2)=0 \n" ); document.write( "(x-1)(x+2)=0 \n" ); document.write( "x=1 or x=-2 \n" ); document.write( "y=4 or y=1 \n" ); document.write( "(1,4) and (-2,1) are the solutions. \n" ); document.write( " |