document.write( "Question 963106: How to solve using the substitution method
\n" ); document.write( "x^2+y=5
\n" ); document.write( "x-y+3=0
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Algebra.Com's Answer #588396 by amarjeeth123(569)\"\" \"About 
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The given equations are
\n" ); document.write( "x^2+y=5.........equation 1
\n" ); document.write( "x-y+3=0.........equation 2
\n" ); document.write( "From equation 2 we get y=x+3.....equation 3
\n" ); document.write( "Substituting in equation 1
\n" ); document.write( "x^2+x+3=5
\n" ); document.write( "x^2+x-2=0
\n" ); document.write( "x^2+2x-x-2=0
\n" ); document.write( "x(x+2)-1(x+2)=0
\n" ); document.write( "(x-1)(x+2)=0
\n" ); document.write( "x=1 or x=-2
\n" ); document.write( "y=4 or y=1
\n" ); document.write( "(1,4) and (-2,1) are the solutions.
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