document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=962966>Question 962966</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A rectangular poster has an area of 190 inches squared the height of a poster is one inch less than twice its width. Find in the dimensions of the poster. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #588346 by </B><A HREF=/tutors/aboutme.mpl?userid=JulietG><B>JulietG(1812)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=JulietG><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=JulietG><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=588346\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> L * W = area<BR>\n" );
document.write( "L * W = 190<BR>\n" );
document.write( "L + 1 = 2W<BR>\n" );
document.write( "Therefore, L = 2W - 1<BR>\n" );
document.write( "The easiest way to do this is to find the factors, and then see what fits.<BR>\n" );
document.write( "Factors of 190 = {190,1}, {95,2}, {5,38}, {19,10}<BR>\n" );
document.write( "In which of these pairs is one number \"twice as much less one\" than the other?<BR>\n" );
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document.write( "The solution is 19,10.  19*10 = 190 square feet.  The length (19) is twice the width (10) minus one. </SPAN>\n" );
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