document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=962933>Question 962933</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The age of a father is three times that of his son. In ten years time their ages will add up to 68. If the son is x years old today, write down an algebraic expression for: the present age of the father, the sons age in 10 years time, the fathers age in 10 years time </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #588327 by </B><A HREF=/tutors/aboutme.mpl?userid=rothauserc><B>rothauserc(4718)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=rothauserc><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=rothauserc><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=588327\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> let x be the age of the father's son,<BR>\n" );
document.write( "father's age = 3x<BR>\n" );
document.write( "x+10 age of son in 10 years<BR>\n" );
document.write( "3x+10 is father's age in 10 years\r<BR>\n" );
document.write( "\n" );
document.write( " </SPAN>\n" );
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