document.write( "Question 962906: If the width of the rectangle is 3 more than the width. What are the dimensions of the rectrangle if its perimeter is 23? \n" ); document.write( "
Algebra.Com's Answer #588291 by macston(5194)\"\" \"About 
You can put this solution on YOUR website!
Problem not possible as written: width cannot be 3 more than the width.
\n" ); document.write( "If length is 3 more than the width:
\n" ); document.write( "W=width; L=length=3W; P=perimeter=23
\n" ); document.write( "P=2(L+W) Substitute for L.
\n" ); document.write( "23=2(W+3+W) Divide each side by 2.
\n" ); document.write( "11.5=2W+3 Subtract 3 from each side
\n" ); document.write( "8.5=2W Divide each side by 2
\n" ); document.write( "4.25=W ANSWER 1: The width is 4.25 units.
\n" ); document.write( "L=W+3=4.25+3=7.25 ANSWER 2: The length is 7.25 units.
\n" ); document.write( "CHECK:
\n" ); document.write( "P=2(L+W)
\n" ); document.write( "23=2(7.25+4.25)
\n" ); document.write( "23=2(11.5)
\n" ); document.write( "23=23
\n" ); document.write( "
\n" ); document.write( "
\n" );