document.write( "Question 962860: Could you help me in these logarhytmes?
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document.write( "3log^2x-2logx=0
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document.write( "Log3x(3logx-4)+1=0 \n" );
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Algebra.Com's Answer #588267 by Alan3354(69443)![]() ![]() You can put this solution on YOUR website! Could you help me in these logarhytmes [sic]? \n" ); document.write( "It's logarithms. \n" ); document.write( "------------ \n" ); document.write( "3log^2x-2logx=0 \n" ); document.write( "log(x)*(3log(x) - 2) = 0 \n" ); document.write( "log(x) = 0 \n" ); document.write( "x = 1 \n" ); document.write( "------------------- \n" ); document.write( "3log(x) - 2 = 0 \n" ); document.write( "log(x) = 2/3 \n" ); document.write( " \n" ); document.write( "x =~ 4.6416 \n" ); document.write( "============================= \n" ); document.write( "Log3x(3logx-4)+1=0 \n" ); document.write( "Clarify: log(3x) or log^3(x) \n" ); document.write( " \n" ); document.write( " |