document.write( "Question 962776: In going a certain distance, a train traveling at the rate of 45.0 mph takes 2.00 hours less than a train traveling 35.0 mph. Find the distance \n" ); document.write( "
Algebra.Com's Answer #588262 by josmiceli(19441)\"\" \"About 
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Let \"+t+\" = time in hrs for the slower train
\n" ); document.write( "slower train:
\n" ); document.write( "(1) \"+d+=+35t+\"
\n" ); document.write( "faster train:
\n" ); document.write( "(2) \"+d+=+45%2A%28+t+-+2+%29+\"
\n" ); document.write( "----------------------
\n" ); document.write( "Set (1) and (2) equal to each other:
\n" ); document.write( "\"+35t+=+45%2A%28+t+-+2+%29+\"
\n" ); document.write( "\"+35t+=+45t+-+90+\"
\n" ); document.write( "\"+10t+=+90+\"
\n" ); document.write( "\"+t+=+9+\"
\n" ); document.write( "\"+t+-+2+=+7+\"
\n" ); document.write( "----------------
\n" ); document.write( "(1) \"+d+=+35t+\"
\n" ); document.write( "(1) \"+d+=+35%2A9+\"
\n" ); document.write( "(1) \"+d+=+315+\"
\n" ); document.write( "the distance is 315 mi
\n" ); document.write( "----------------------
\n" ); document.write( "check:
\n" ); document.write( "(2) \"+d+=+45%2A%28+t+-+2+%29+\"
\n" ); document.write( "(2) \"+d+=+45%2A7+\"
\n" ); document.write( "(2) \"+d+=+315+\"
\n" ); document.write( "OK\r
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