document.write( "Question 962815: solve the equation, [0, 2pi)
\n" ); document.write( "a) cos(pi/2+x)-cos(pi/2-x)=√2
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Algebra.Com's Answer #588238 by lwsshak3(11628)\"\" \"About 
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solve the equation, [0, 2pi)
\n" ); document.write( "a) cos(pi/2+x)-cos(pi/2-x)=√2
\n" ); document.write( "(cos(π/2)*cosx-sin(π/2)*sinx-[(cos(π/2)*cosx+sin(π/2)*sinx]=√2
\n" ); document.write( "0*cosx-1*sinx-0*cosx-1*sinx=√2
\n" ); document.write( "-2sinx=√2
\n" ); document.write( "sinx=-√2/2
\n" ); document.write( "x=3π/4, 5π/4
\n" ); document.write( "
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