document.write( "Question 962807: If distance ‘s’ is a function of time ‘t’ given by s = t3 – 6t2 – 15t + 12 then the velocity when acceleration is 0 is \n" ); document.write( "

Algebra.Com's Answer #588232 by amarjeeth123(569) $\"\"$ $\"About$

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s = t3 – 6t2 – 15t + 12
\n" ); document.write( "Velocity v=ds/dt=3t2-12t-15
\n" ); document.write( "Acceleration=dv/dt=6t-12
\n" ); document.write( "When acceleration is zero we have 6t-12=0
\n" ); document.write( "t=2 sec
\n" ); document.write( "Velocity v=3(2)^2-12(2)-15=12-24-15=-27 units \n" ); document.write( "

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