document.write( "Question 82113: My directions are to solve the system by substitution. I don't know what I did wrong, but when I went to recheck my work I did not come up with the right answer could someone please re-work this problem and tell me what I did wrong.
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document.write( "3x+3y=9
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document.write( "y=2x-12\r
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document.write( "My work
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document.write( "3x+3(2x-12)=9 y=2(50
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document.write( "3x+6x-36=9 =10-12
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document.write( "9x/9=45/9 = -2
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document.write( "x=5
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document.write( "(5,-2)\r
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document.write( "To Check
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document.write( "5+ -2=7
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document.write( "7+ -2=9 \n" );
document.write( "
Algebra.Com's Answer #58822 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! 3x+3y=9 \n" ); document.write( "y=2x-12 \n" ); document.write( "------------ \n" ); document.write( "You have x=5, y=-2 \n" ); document.write( "Check: \n" ); document.write( "3(5)+3(-2)=9 \n" ); document.write( "15-6=9 \n" ); document.write( "9=9 \n" ); document.write( "------- \n" ); document.write( "or \n" ); document.write( "-2=2(5)-12 \n" ); document.write( "-2=10-12 \n" ); document.write( "-2=-2 \n" ); document.write( "============ \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( " |