document.write( "Question 962703: A chemist wants to mix three different solutions to create 100 milliliters of a solution that is 13.5% alcohol.Solution A is 10% alcohol, solution B is 15% alcohol and solution C is 30% alcohol. The amount of solution A that is used must be twice the amount of solution B that is used.How many milliliters of each solution should be the chemist combine?\r
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Algebra.Com's Answer #588216 by ankor@dixie-net.com(22740)\"\" \"About 
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let a = amt of 10%
\n" ); document.write( "let b = amt of 15%
\n" ); document.write( "let c = amt of 30%
\n" ); document.write( ":
\n" ); document.write( "A chemist wants to mix three different solutions to create 100 milliliters of a solution that is 13.5% alcohol.
\n" ); document.write( "Solution A is 10% alcohol,
\n" ); document.write( "solution B is 15% alcohol and
\n" ); document.write( "solution C is 30% alcohol.
\n" ); document.write( "The amount of solution A that is used must be twice the amount of solution B that is used.
\n" ); document.write( "a = 2b
\n" ); document.write( "a + b + c = 100
\n" ); document.write( "replace a with 2b
\n" ); document.write( "2b + b + c = 100
\n" ); document.write( "3b + c = 100
\n" ); document.write( "then
\n" ); document.write( "c = (-3b+100)
\n" ); document.write( "the mixture equation
\n" ); document.write( ".10a + .15b + .30c = .135(100)
\n" ); document.write( "replace a with 2b, replace c with (-3b+100)
\n" ); document.write( ".10(2b) + .15b + .30(-3b+100) = 13.5
\n" ); document.write( ".20b + .15b - .90b + 30 = 13.5
\n" ); document.write( "-.55b = 13.5 - 30
\n" ); document.write( "-.55b = -16.5
\n" ); document.write( "b = -16.5/-.55
\n" ); document.write( "b = + 30 ml of 15% solution
\n" ); document.write( "then
\n" ); document.write( "2(30) = 60 ml of 10% solution
\n" ); document.write( "and
\n" ); document.write( "100-30-60 = 10 ml of 30% solution
\n" ); document.write( ":
\n" ); document.write( ":
\n" ); document.write( "Confirm this, see if:
\n" ); document.write( ".10(60) + .15(30) + .30(10) = .135(100)
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