document.write( "Question 962731: Hello can you please help me solve this problem: (the straight lines are meant to show absolute value)
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Algebra.Com's Answer #588209 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
2*|3x-1| +1 < 5\r
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\n" ); document.write( "\n" ); document.write( "2*|3x-1| +1-1 < 5-1 ... Subtract 1 from both sides.\r
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\n" ); document.write( "\n" ); document.write( "2*|3x-1| < 4\r
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\n" ); document.write( "\n" ); document.write( "2*|3x-1|/2 < 4/2 ... Divide both sides by 2.\r
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\n" ); document.write( "\n" ); document.write( "|3x-1| < 2\r
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\n" ); document.write( "\n" ); document.write( "-2 < 3x-1 < 2\r
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\n" ); document.write( "\n" ); document.write( "-2+1 < 3x-1+1 < 2+1 ... Add 1 to all sides.\r
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\n" ); document.write( "\n" ); document.write( "-1 < 3x < 3\r
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\n" ); document.write( "\n" ); document.write( "-1/3 < 3x/3 < 3/3 ... Divide all sides by 3\r
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\n" ); document.write( "\n" ); document.write( "-1/3 < x < 1\r
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\n" ); document.write( "\n" ); document.write( "So the final answer is -1/3 < x < 1\r
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\n" ); document.write( "\n" ); document.write( "If you need more one-on-one help, or if you have any questions, email me at jim_thompson5910@hotmail.com
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