document.write( "Question 962665: X is a normally distributed random variable with a mean of 10.00. If the probability that X is less than 11.54 is 0.67 (as shown below), then what is the standard deviation of X? Round to 2 decimal places. \n" ); document.write( "
Algebra.Com's Answer #588176 by jim_thompson5910(35256)\"\" \"About 
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P(Z < z) = 0.67 has the solution z = 0.4399\r
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\n" ); document.write( "\n" ); document.write( "So P(Z < 0.4399) = 0.67 approximately\r
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\n" ); document.write( "\n" ); document.write( "You use a calculator or table to determine this.\r
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\n" ); document.write( "\n" ); document.write( "z = (x-mu)/sigma\r
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\n" ); document.write( "\n" ); document.write( "0.4399 = (11.54-10)/sigma\r
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\n" ); document.write( "\n" ); document.write( "0.4399 = 1.54/sigma\r
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\n" ); document.write( "\n" ); document.write( "0.4399*sigma = 1.54\r
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\n" ); document.write( "\n" ); document.write( "sigma = 1.54/0.4399\r
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\n" ); document.write( "\n" ); document.write( "sigma = 3.5007956\r
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\n" ); document.write( "\n" ); document.write( "sigma = 3.50\r
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\n" ); document.write( "\n" ); document.write( "The standard deviation is approximtely 3.50\r
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\n" ); document.write( "\n" ); document.write( "If you need more one-on-one help, or if you have any questions, email me at jim_thompson5910@hotmail.com
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