document.write( "Question 962634: Can I have help please
\n" ); document.write( "\"Solve by factoring
\n" ); document.write( "\"2x%5E2-7x-4=0\"\"
\n" ); document.write( "We are using the zero product property, but there are no multiples of 4 that goes into 7. \n" ); document.write( "
Algebra.Com's Answer #588169 by Theo(13342)\"\" \"About 
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2x^2 - 7x - 4 = 0
\n" ); document.write( "multiply 2 * 4 to get 8
\n" ); document.write( "look for the factors of 8 that add up to or subtract from each other to get -7
\n" ); document.write( "since the coefficient of the x term is negative and the coefficient of the constant term is also negative, you will be looking for factors that subtract from each other to get 7.\r
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\n" ); document.write( "\n" ); document.write( "8 * 1 = 8 and 8 - 1 = 7
\n" ); document.write( "they look like they'll do.\r
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\n" ); document.write( "\n" ); document.write( "split the middle term into -8x and +x to get:
\n" ); document.write( "2x^2 - 8x + x - 4 = 0
\n" ); document.write( "associate the first two terms together and the last two terms together to get:
\n" ); document.write( "(2x^2 - 8x + (x - 4) = 0
\n" ); document.write( "factor the first associated terms so that (x - 4) is one of the factors.
\n" ); document.write( "you will get:
\n" ); document.write( "2x * (x-4) + (x-4) = 0
\n" ); document.write( "this is equivalent to:
\n" ); document.write( "2x * (x-4) + 1 * (x-4) = 0
\n" ); document.write( "factor out the common term of (x-4) to get:
\n" ); document.write( "(2x + 1) * (x-4) = 0
\n" ); document.write( "those are your factors.\r
\n" ); document.write( "\n" ); document.write( "read this tutorial on factoring.
\n" ); document.write( "it should help.
\n" ); document.write( "http://www.purplemath.com/modules/factquad.htm
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