document.write( "Question 962596: a number, one fourth of that number, and one third of that number are added. the result is 19. what is the.original number \n" ); document.write( "
Algebra.Com's Answer #588159 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! a number, one fourth of that number, and one third of that number are added. the result is 19. \n" ); document.write( "n + \n" ); document.write( "multiply equation by 12, then cancel the denominators \n" ); document.write( "12n + 3n + 4n = 12(19) \n" ); document.write( "19n = 12(19) \n" ); document.write( "divide both sides by 19 \n" ); document.write( "n = 12\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |