document.write( "Question 962596: a number, one fourth of that number, and one third of that number are added. the result is 19. what is the.original number \n" ); document.write( "
Algebra.Com's Answer #588159 by ankor@dixie-net.com(22740)\"\" \"About 
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a number, one fourth of that number, and one third of that number are added. the result is 19.
\n" ); document.write( "n + \"1%2F4\"n + \"1%2F3\"n = 19
\n" ); document.write( "multiply equation by 12, then cancel the denominators
\n" ); document.write( "12n + 3n + 4n = 12(19)
\n" ); document.write( "19n = 12(19)
\n" ); document.write( "divide both sides by 19
\n" ); document.write( "n = 12\r
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