document.write( "Question 82013: Mike, a salvation army bell ringer, has 5 fewer quarters than nickels in his cup. If Mike has $5.95 in quarters and nickels, how many nickels does he have?\r
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document.write( "I need help extracting the algebraic equation from this story problem. \n" );
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Algebra.Com's Answer #58811 by ptaylor(2198)![]() ![]() You can put this solution on YOUR website! Let x=number of nickels in Mike's cup \n" ); document.write( "Then x-5=number of quarters in Mike's cup\r \n" ); document.write( "\n" ); document.write( "Let's now deal in pennies to make life a little more simple.\r \n" ); document.write( "\n" ); document.write( "5x=amount of money that Mike has from the nickels\r \n" ); document.write( "\n" ); document.write( "25(x-5)=amount of money that Mike has from the quarters\r \n" ); document.write( "\n" ); document.write( "We are told that this adds up to 595. So our algebraic equation is:\r \n" ); document.write( "\n" ); document.write( "5x+25(x-5)=595 get rid of parens (Now as you well know, if we want to deal in dollars, we can just as easily write this equation as: \n" ); document.write( "0.05x+0.25(x-5)=5.95), but lets continue to deal in pennies\r \n" ); document.write( "\n" ); document.write( "5x+25x-125=595 add 125 to both sides \n" ); document.write( "5x+25x-125+125=595+125 collect like terms\r \n" ); document.write( "\n" ); document.write( "30x=720 divide both sides by 30 \n" ); document.write( "x=24------------------------------------number of nickels\r \n" ); document.write( "\n" ); document.write( "x-5=24-5=19---------------------------------number of quarters\r \n" ); document.write( "\n" ); document.write( "CK \n" ); document.write( "24(0.05)+19(0.25)=5.95 \n" ); document.write( "1.20+4.75=5.95 \n" ); document.write( "5.95=5.95\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Hope this helps----ptaylor\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |