document.write( "Question 962440: When 80% of a number is added to 10 the result is 14 more than 20% of twice the number \n" ); document.write( "
Algebra.Com's Answer #588034 by MathLover1(20850)\"\" \"About 
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\n" ); document.write( "let a number be \"x\"
\n" ); document.write( "\"80\"%=\"0.80\" of a number is \"0.80x\"
\n" ); document.write( "\"20\"%=\"0.20\"\r
\n" ); document.write( "\n" ); document.write( "if added \"0.80x\" to \"10\", we have \"10%2B0.80x\" \r
\n" ); document.write( "\n" ); document.write( "if the result is \"14\" more than \"0.20\" of twice the number \"%282x%29\", then we have\r
\n" ); document.write( "\n" ); document.write( "\"10%2B0.80x=0.20%282x%29%2B14\"........solve for \"x\" \r
\n" ); document.write( "\n" ); document.write( "\"10%2B0.80x=0.40x%2B14\"\r
\n" ); document.write( "\n" ); document.write( "\"0.80x-0.40x=14-10\"\r
\n" ); document.write( "\n" ); document.write( "\"0.40x=4\"\r
\n" ); document.write( "\n" ); document.write( "\"x=4%2F0.40\"\r
\n" ); document.write( "\n" ); document.write( "\"x=400%2F40\"\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"highlight%28x=10%29\"\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "check:\r
\n" ); document.write( "\n" ); document.write( "\"80\"% of \"10\" is \"0.80%2A10=8\"\r
\n" ); document.write( "\n" ); document.write( "\"20\"% of \"2%2A10\" is \"0.20%2A20=4\"\r
\n" ); document.write( "\n" ); document.write( "\"10%2B0.80x=10%2B8=18\"\r
\n" ); document.write( "\n" ); document.write( "\"0.20%282x%29%2B14=4%2B14=18\" \r
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