document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=82047>Question 82047</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Solve by using either addition or substitution. If a unique solution does not exist; state whether the system is dependent or inconsistent:\r<BR>\n" );
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document.write( "10x+2y=7<BR>\n" );
document.write( "    y=-5x+3 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #58801 by </B><A HREF=/tutors/aboutme.mpl?userid=jayanthihemkos@yahoo.com><B>jayanthihemkos@yahoo.com(87)</B></A><img src=\"/images/stars/stars-08.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=jayanthihemkos@yahoo.com><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=58801\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 10x+2y=7--------(1)\r<BR>\n" );
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document.write( "    y=-5x+3-------(2)\r<BR>\n" );
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document.write( "plugging the value of y from equation(2) into equation (1) ,we have\r<BR>\n" );
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document.write( "10x+2(-5x+3) =7\r<BR>\n" );
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document.write( "10x -10x+6 = 7\r<BR>\n" );
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document.write( "since we have +10x and -10x in the above equation they get cancelled \r<BR>\n" );
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document.write( "Hence there is no solution \r<BR>\n" );
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document.write( "Hence  the system is inconsistent </SPAN>\n" );
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