document.write( "Question 962394: The measure of the three angles in a triangle must total of 180 degrees. The measure of angle A is 20 degrees less than the measure of angle C. The measure of angle C is twice the measure of angle B. Find the measure of each angle.\r
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Algebra.Com's Answer #587988 by macston(5194)\"\" \"About 
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\n" ); document.write( "A=C-20; C=2B
\n" ); document.write( "2B=C
\n" ); document.write( "B=C/2
\n" ); document.write( "A+B+C=180 Substitute for A and B.
\n" ); document.write( "(C-20)+(C/2)+C=180
\n" ); document.write( "2.5C-20=180 Add 20 to each side.
\n" ); document.write( "2.5C=200 Divide each side by 2.5.
\n" ); document.write( "C=80 ANSWER 1: Angle C is 80 degrees.
\n" ); document.write( "B=C/2=80/2=40 ANSWER 2: Angle B is 40 degrees.
\n" ); document.write( "A=C-20=80-20=60 ANSWER 3: Angle A is 60 degrees.
\n" ); document.write( "CHECK:
\n" ); document.write( "A+B+C=180 degrees
\n" ); document.write( "60 degrees+40 degrees+80 degrees=180 degrees
\n" ); document.write( "180 degrees=180 degrees\r
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