document.write( "Question 962400: A poster is three times as long as it is wide. It is framed by a mat such that there is a 4 in. border around the poster. Find the dimensions of the poster is the area of the mat is 488 in^2. \n" ); document.write( "

Algebra.Com's Answer #587987 by josmiceli(19441) $\"\"$ $\"About$

You can put this solution on YOUR website!
Let $\"+w+\"$ = width of the poster
\n" ); document.write( " $\"+3w+\"$ = the length of the poster
\n" ); document.write( "-------------------------------
\n" ); document.write( " $\"+w+%2B+8+%29%2A%28+2w+%2B+8+%29+=+w%2A%282w%29+%2B+488+\"$
\n" ); document.write( " $\"+2w%5E2+=+16w+%2B+8w+%2B+64++=+2w%5E2+%2B+488+\"$
\n" ); document.write( " $\"+24w+%2B+64+=+488+\"$
\n" ); document.write( " $\"+24w+=+424+\"$
\n" ); document.write( " $\"+w+=+17.667+\"$
\n" ); document.write( " $\"+2w+=+35.333++\"$
\n" ); document.write( "-------------------
\n" ); document.write( "The dimensions of the poster are:
\n" ); document.write( "17 and 2/3 inches x 35 and 1/3 inches
\n" ); document.write( "-------------------
\n" ); document.write( "check:
\n" ); document.write( " $\"+w+%2B+8+%29%2A%28+2w+%2B+8+%29+=+w%2A%282w%29+%2B+488+\"$
\n" ); document.write( " $\"+17.667+%2B+8+%29%2A%28+35.333+%2B+8+%29+=+17.667%2A35.333+%2B+488+\"$
\n" ); document.write( " $\"+25.667%2A43.333+=+624.228+%2B+488+\"$
\n" ); document.write( " $\"+1112.228+=+1112.228+\"$
\n" ); document.write( "looks good -hope I got it\r
\n" ); document.write( "\n" ); document.write( " \n" ); document.write( "

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