document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=962389>Question 962389</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A boat traveled for 3hr with a 2mph current to reach a picnic area. The return trip against the same current took 6hr. Find the speed of the boat in still water<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #587982 by </B><A HREF=/tutors/aboutme.mpl?userid=macston><B>macston(5194)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=macston><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=macston><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=587982\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> .<BR>\n" );
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document.write( "S=speed in still water<BR>\n" );
document.write( "3hr(S+2mph)=6hr(S-2mph)<BR>\n" );
document.write( "3hrS+6mi=6hrS-12mi Add 12 mi to each side.<BR>\n" );
document.write( "3hrS+18mi=6hrS Subtract 3hrS from each side<BR>\n" );
document.write( "18mi=3hrS Divide each side by 3 Hr<BR>\n" );
document.write( "18mi/3hr=6 mph=S ANSWER: The boats rate in still water was 6 mph.<BR>\n" );
document.write( "CHECK:<BR>\n" );
document.write( "3hr(S+2mph)=6hr(S-2mph)<BR>\n" );
document.write( "3hr(6mph+2mph)=6hr(6mph-2mph)<BR>\n" );
document.write( "3hr(8mph)=6hr(4mph)<BR>\n" );
document.write( "24mi=24mi </SPAN>\n" );
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