document.write( "Question 962395: A total investment of $10,200 is made into two savings accounts. One account yields 8% simple interest and the other 10% simple interest. He earns a total of $978.00 interest for the year. How much was invested in the 8% account? \n" ); document.write( "
Algebra.Com's Answer #587980 by macston(5194)![]() ![]() You can put this solution on YOUR website! E=amount at 8%; T=amount at 10% \n" ); document.write( "E+T=$10200 \n" ); document.write( "T=$10200-E Use this to substitute for T. \n" ); document.write( "0.08E+0.10T=$978 Substitute for T. \n" ); document.write( "0.08E+0.10($10200-E)=$978 \n" ); document.write( "0.08E+$1020-0.10E=$978 Subtract $1020 from each side. \n" ); document.write( "-0.02E=-$42 Divide each side by -0.02. \n" ); document.write( "E=$2100 ANSWER: $2100 was invested at 8%. \n" ); document.write( "CHECK: \n" ); document.write( "T=$10200-E \n" ); document.write( "T=$10200-$2100=$8100 $8100 was invested at 10% \n" ); document.write( "0.08E+0.10T=$978 \n" ); document.write( "0.08($2100)+0.10($8100)=$978 \n" ); document.write( "$168+$810=$978 \n" ); document.write( "$978=$978 \n" ); document.write( " |