document.write( "Question 962387: How to use an elimination strategy to solve the linear system: \r
\n" ); document.write( "\n" ); document.write( "5/3x +1/4y = 10
\n" ); document.write( "1/3x + 1/2y = 5\r
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\n" ); document.write( "\n" ); document.write( "ans:
\n" ); document.write( "(5/3x +1/4y = 10 ) * 12 --> 30x+3y=120
\n" ); document.write( "(1/3x + 1/2y = 5) * 6 --> 2x+3y=30\r
\n" ); document.write( "\n" ); document.write( "I never seem to get the answer right everything I check the solution. Plz help me correct it ??
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Algebra.Com's Answer #587976 by MathLover1(20850)\"\" \"About 
You can put this solution on YOUR website!
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Solved by pluggable solver: Solving a System of Linear Equations by Elimination/Addition
TEST
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\n" ); document.write( " \"%285%2F3%29%2Ax%2B%281%2F4%29%2Ay=10\" Start with the first equation
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\n" ); document.write( " \"12%28%285%2F3%29%2Ax%2B%281%2F4%29%2Ay%29=%2812%29%2A%2810%29\" Multiply both sides by the LCD 12
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\n" ); document.write( " \"20%2Ax%2B3%2Ay=120\"Distribute and simplify
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\n" ); document.write( " \"%281%2F3%29%2Ax%2B%281%2F2%29%2Ay=5\" Start with the second equation
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\n" ); document.write( " \"6%28%281%2F3%29%2Ax%2B%281%2F2%29%2Ay%29=%286%29%2A%285%29\" Multiply both sides by the LCD 6
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\n" ); document.write( " \"2%2Ax%2B3%2Ay=30\" Distribute and simplify
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\n" ); document.write( " Lets start with the given system of linear equations
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\n" ); document.write( " \"20%2Ax%2B3%2Ay=120\"
\n" ); document.write( " \"2%2Ax%2B3%2Ay=30\"
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\n" ); document.write( " In order to solve for one variable, we must eliminate the other variable. So if we wanted to solve for y, we would have to eliminate x (or vice versa).
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\n" ); document.write( " So lets eliminate x. In order to do that, we need to have both x coefficients that are equal but have opposite signs (for instance 2 and -2 are equal but have opposite signs). This way they will add to zero.
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\n" ); document.write( " So to make the x coefficients equal but opposite, we need to multiply both x coefficients by some number to get them to an equal number. So if we wanted to get 20 and 2 to some equal number, we could try to get them to the LCM.
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\n" ); document.write( " Since the LCM of 20 and 2 is 20, we need to multiply both sides of the top equation by 1 and multiply both sides of the bottom equation by -10 like this:
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\n" ); document.write( " \"1%2A%2820%2Ax%2B3%2Ay%29=%28120%29%2A1\" Multiply the top equation (both sides) by 1
\n" ); document.write( " \"-10%2A%282%2Ax%2B3%2Ay%29=%2830%29%2A-10\" Multiply the bottom equation (both sides) by -10
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\n" ); document.write( " So after multiplying we get this:
\n" ); document.write( " \"20%2Ax%2B3%2Ay=120\"
\n" ); document.write( " \"-20%2Ax-30%2Ay=-300\"
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\n" ); document.write( " Notice how 20 and -20 add to zero (ie \"20%2B-20=0\")
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\n" ); document.write( " Now add the equations together. In order to add 2 equations, group like terms and combine them
\n" ); document.write( " \"%2820%2Ax-20%2Ax%29%2B%283%2Ay-30%2Ay%29=120-300\"
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\n" ); document.write( " \"%2820-20%29%2Ax%2B%283-30%29y=120-300\"
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\n" ); document.write( " \"cross%2820%2B-20%29%2Ax%2B%283-30%29%2Ay=120-300\" Notice the x coefficients add to zero and cancel out. This means we've eliminated x altogether.
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\n" ); document.write( " So after adding and canceling out the x terms we're left with:
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\n" ); document.write( " \"-27%2Ay=-180\"
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\n" ); document.write( " \"y=-180%2F-27\" Divide both sides by \"-27\" to solve for y
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\n" ); document.write( " \"y=20%2F3\" Reduce
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\n" ); document.write( " Now plug this answer into the top equation \"20%2Ax%2B3%2Ay=120\" to solve for x
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\n" ); document.write( " \"20%2Ax%2B3%2820%2F3%29=120\" Plug in \"y=20%2F3\"
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\n" ); document.write( " \"20%2Ax%2B60%2F3=120\" Multiply
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\n" ); document.write( " \"20%2Ax%2B20=120\" Reduce
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\n" ); document.write( " \"20%2Ax=120-20\" Subtract \"20\" from both sides
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\n" ); document.write( " \"20%2Ax=100\" Combine the terms on the right side
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\n" ); document.write( " \"cross%28%281%2F20%29%2820%29%29%2Ax=%28100%29%281%2F20%29\" Multiply both sides by \"1%2F20\". This will cancel out \"20\" on the left side.
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\n" ); document.write( " \"x=5\" Multiply the terms on the right side
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\n" ); document.write( " So our answer is
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\n" ); document.write( " \"x=5\", \"y=20%2F3\"
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\n" ); document.write( " which also looks like
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\n" ); document.write( " (\"5\", \"20%2F3\")
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\n" ); document.write( " Notice if we graph the equations (if you need help with graphing, check out this solver)
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\n" ); document.write( " \"20%2Ax%2B3%2Ay=120\"
\n" ); document.write( " \"2%2Ax%2B3%2Ay=30\"
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\n" ); document.write( " we get
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\n" ); document.write( " graph of \"20%2Ax%2B3%2Ay=120\" (red) \"2%2Ax%2B3%2Ay=30\" (green) (hint: you may have to solve for y to graph these) and the intersection of the lines (blue circle).
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\n" ); document.write( " and we can see that the two equations intersect at (\"5\",\"20%2F3\"). This verifies our answer.
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