document.write( "Question 962250: An open rectangular box with square base and open top is to contain 1000cm^3.Find the dimensions that require the least amount of material.Neglect the thickness of the material and waste in construction.(Hint:Here we are looking at surface area)\r
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Algebra.Com's Answer #587969 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! An open rectangular box with square base and open top is to contain 1000cm^3. \n" ); document.write( "Find the dimensions that require the least amount of material. \n" ); document.write( ": \n" ); document.write( "let x = side of the square base \n" ); document.write( "let h = the height of the box \n" ); document.write( "then the volume \n" ); document.write( "x * x * h = 1000 \n" ); document.write( "x^2h = 1000 \n" ); document.write( "h = \n" ); document.write( ": \n" ); document.write( "The surface area of an open box \n" ); document.write( ": \n" ); document.write( "S.A. = bottom area + 4 side areas \n" ); document.write( "S.A. = x^2 + 4(x*h) \n" ); document.write( "Replace h with \n" ); document.write( "S.A. = x^2 + 4(x* \n" ); document.write( "cancel x into x^2 \n" ); document.write( "S.A. = x^2 + \n" ); document.write( "Graph this in your graphing calc S.A. = y \n" ); document.write( " \n" ); document.write( "minimum surface when x = 12.6 cm the side of the square base \n" ); document.write( "Find the height \n" ); document.write( "h = \n" ); document.write( "h = \n" ); document.write( "h = 6.3 cm is the height \n" ); document.write( ": \n" ); document.write( "Summarize, 12.6 by 12.6 by 6.3 dimensions for minimum surface area \n" ); document.write( ": \n" ); document.write( "confirm this by finding the volume with these dimension \n" ); document.write( "12.6 * 12.6 * 6.3 = 1000.2, close enough \n" ); document.write( " \n" ); document.write( " |