document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=962372>Question 962372</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Jessica needs 12lb of metal with 43% silver. If Jessica combines one metal with 12% silver, and another with 79% silver. How much of each metal does Jessica need?  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #587966 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=587966\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Jessica needs 12 lb of metal with 43% silver. If Jessica combines one metal with 12% silver, and another with 79% silver. How much of each metal does Jessica need? <BR>\n" );
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document.write( "Equations:<BR>\n" );
document.write( "silver + silver = silver<BR>\n" );
document.write( "0.12x + 0.79(12-x) = 0.43*12<BR>\n" );
document.write( "12x + 79*12 - 79x = 43*12<BR>\n" );
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document.write( "-67x = -36*12<BR>\n" );
document.write( "x = 6.45 lb (amt. of 12% alloy needed)<BR>\n" );
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document.write( "12-x = 5.55 lb (amt. of 79% alloy needed)<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
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