document.write( "Question 962349: Write the vertex of the following equation:\r
\n" ); document.write( "\n" ); document.write( "f(x)= (x+3)squared + 2\r
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Algebra.Com's Answer #587942 by rothauserc(4718)\"\" \"About 
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f(x)= (x+3)squared + 2
\n" ); document.write( "f(x) = x^2 +6x +9 +2
\n" ); document.write( "f(x) = x^2 +6x +11
\n" ); document.write( "the axis of symmetry for the parabola is
\n" ); document.write( "x = -b / 2a = -6 / 2 = -3
\n" ); document.write( "so far we have the following for the vertex (-3, y)
\n" ); document.write( "substitute for x in the equation
\n" ); document.write( "y = f(x) = x^2 +6x +11
\n" ); document.write( "y = f(x) = (-3)^2 + (6*-3) + 11
\n" ); document.write( "y = f(x) = 9 - 18 + 11
\n" ); document.write( "y = f(x) = 2
\n" ); document.write( "the vertex of the parabola is (-3, 2)
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