document.write( "Question 962349: Write the vertex of the following equation:\r
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document.write( "f(x)= (x+3)squared + 2\r
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Algebra.Com's Answer #587942 by rothauserc(4718) You can put this solution on YOUR website! f(x)= (x+3)squared + 2 \n" ); document.write( "f(x) = x^2 +6x +9 +2 \n" ); document.write( "f(x) = x^2 +6x +11 \n" ); document.write( "the axis of symmetry for the parabola is \n" ); document.write( "x = -b / 2a = -6 / 2 = -3 \n" ); document.write( "so far we have the following for the vertex (-3, y) \n" ); document.write( "substitute for x in the equation \n" ); document.write( "y = f(x) = x^2 +6x +11 \n" ); document.write( "y = f(x) = (-3)^2 + (6*-3) + 11 \n" ); document.write( "y = f(x) = 9 - 18 + 11 \n" ); document.write( "y = f(x) = 2 \n" ); document.write( "the vertex of the parabola is (-3, 2) \n" ); document.write( " \n" ); document.write( " |