document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=962343>Question 962343</A>: <I><SPAN STYLE=\"word-break: break-all;\"> these are some problems my son has in the 7th grade and I don't know how to help him. I have tried many web sites and all I could find are calculators but it does not help him understand the steps. Mostly when are you supposed to to add but really subtract?<BR>\n" );
document.write( "2/5 + 3/2y = 1/2\r<BR>\n" );
document.write( "\n" );
document.write( "1/2 (4-d) = 2/5\r<BR>\n" );
document.write( "\n" );
document.write( "3 (x + 2/9) = 2/3\r<BR>\n" );
document.write( "\n" );
document.write( "9/10 + b = 3/4<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #587941 by </B><A HREF=/tutors/aboutme.mpl?userid=rothauserc><B>rothauserc(4718)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=rothauserc><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=rothauserc><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=587941\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> a) 2/5 + 3/2y = 1/2<BR>\n" );
document.write( "b) 1/2 (4-d) = 2/5<BR>\n" );
document.write( "c) 3 (x + 2/9) = 2/3<BR>\n" );
document.write( "d) 9/10 + b = 3/4<BR>\n" );
document.write( "****************************<BR>\n" );
document.write( "a) 2/5 + 3/2y = 1/2<BR>\n" );
document.write( "subtract 2/5 from both sides of =<BR>\n" );
document.write( "3/2y = 1/2 - 2/5<BR>\n" );
document.write( "put fractions on right side of = over a common denominator<BR>\n" );
document.write( "3/2y = 5/10 - 4/10<BR>\n" );
document.write( "3/2y = 1/10<BR>\n" );
document.write( "cross multiply the fractions<BR>\n" );
document.write( "30 = 2y<BR>\n" );
document.write( "y = 15<BR>\n" );
document.write( "now substitute for y in original equation to check answer for y<BR>\n" );
document.write( "2/5 + 3/ (2*15) = 1/2<BR>\n" );
document.write( "2/5 + 3/30 = 1/2<BR>\n" );
document.write( "12/30 + 3/30 = 1/2 <BR>\n" );
document.write( "15/30 = 1/2<BR>\n" );
document.write( "1/2 = 1/2<BR>\n" );
document.write( "our answer checks<BR>\n" );
document.write( "*******************************<BR>\n" );
document.write( "b) 1/2 (4-d) = 2/5<BR>\n" );
document.write( "multiply both sides of = by 2<BR>\n" );
document.write( "4 - d = 4/5<BR>\n" );
document.write( "subtract 4 from both sides of =<BR>\n" );
document.write( "-d = 4/5 - 4<BR>\n" );
document.write( "-d = 4/5 - 20/5<BR>\n" );
document.write( "-d = -16/5<BR>\n" );
document.write( "d = 16/5<BR>\n" );
document.write( "nod substitute for d in original equation to check answer<BR>\n" );
document.write( "1/2 (4 - 16/5) = 2/5<BR>\n" );
document.write( "1/2 (20/5 - 16/5) = 2/5<BR>\n" );
document.write( "1/2 * 4/5 = 2/5<BR>\n" );
document.write( "2/5 = 2/5<BR>\n" );
document.write( "our answer for y checks<BR>\n" );
document.write( "*************************************<BR>\n" );
document.write( "c) 3 (x + 2/9) = 2/3<BR>\n" );
document.write( "divide both sides of = by 3<BR>\n" );
document.write( "x + 2/9 = 2/9<BR>\n" );
document.write( "x = 0<BR>\n" );
document.write( "substitute for x<BR>\n" );
document.write( "3 * (0 + 2/9) = 2/3<BR>\n" );
document.write( "6/9 = 2/3<BR>\n" );
document.write( "2/3 = 2/3<BR>\n" );
document.write( "our answer checks<BR>\n" );
document.write( "**************************************<BR>\n" );
document.write( "d) 9/10 + b = 3/4<BR>\n" );
document.write( "subtract 9/10 from both sides of =<BR>\n" );
document.write( "b = 3/4 - 9/10<BR>\n" );
document.write( "b = 15/20 - 18/20<BR>\n" );
document.write( "b = -3/20<BR>\n" );
document.write( "substitute for b<BR>\n" );
document.write( "9/10 - 3/20 = 3/4<BR>\n" );
document.write( "18/20 - 3/20 = 3/4<BR>\n" );
document.write( "15/20 = 3/4<BR>\n" );
document.write( "3/4 = 3/4<BR>\n" );
document.write( "our answer for y checks<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );