document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=962332>Question 962332</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Number 142 is divided into two parts such that when the greater part is divided by the smaller, the quotient is 3 and the remainder is 14. What are these parts? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #587936 by </B><A HREF=/tutors/aboutme.mpl?userid=jjthomson83><B>jjthomson83(4)</B></A><img src=\"/images/stars/iconNewId_16x16.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=jjthomson83><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=jjthomson83><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=587936\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let x and y be the greater and smaller numbers respectively<BR>\n" );
document.write( "x+y=142<BR>\n" );
document.write( "3y+14=x ie quotient × divisor +remainder= dividend<BR>\n" );
document.write( "divisor=y, dividend=x , remainder=14 and quotient=3\r<BR>\n" );
document.write( "\n" );
document.write( "x+y=142<BR>\n" );
document.write( "x-3y=14<BR>\n" );
document.write( "4y=128<BR>\n" );
document.write( "y=32<BR>\n" );
document.write( "x=142-32<BR>\n" );
document.write( "=110<BR>\n" );
document.write( "hence x=110 and y=32 </SPAN>\n" );
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